an edge of a cube is increase by 10%. find the percentage bu which the surface area of the cube has increased???
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surface area of a cube =6a*a
so 6*10*10=600
then 10*10/100=1
so 6*11*11=726
so 726-600=126
so 600/126*100=30000/43
so 6*10*10=600
then 10*10/100=1
so 6*11*11=726
so 726-600=126
so 600/126*100=30000/43
avni2:
thankyou but it is wrong answer...correct answer is 21% ok...
how pls explain it
i m 6 std
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