an edge of a cube is increased by 10% find a percent by which the surface area of cube increase
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Answered by
50
here is ur anwer;;bro
Let, the edge of the square = 100
Increased by 10%
therefore, New edge will be 110
Surface Area of a square = 6 * (100)^2
= 60000
Surface area of square with new edge = 6*(110)^2
= 72600
% increased in surface area = [(72600 - 60000)/60000] * 100
=21% ans
aman536:
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Answered by
7
original surface area is 6a2
new surface area is 6(11a/10)2= 121×6a2/100= 726a2/100
required percent = 1.26%
new surface area is 6(11a/10)2= 121×6a2/100= 726a2/100
required percent = 1.26%
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