Question

An edge of a cube is increased by 10%.Find the percent by which the surface area of the cube has increased.

Answer 1

let the side of the cube a.
therefore, the surface area of the cube=6a²
when the the side is increased by 10℅
the side becomes 11/10 of a
there fore, the the surface area=6(11a/10)²
=726a²/100
therefore, the increase= 726a²/100- 6a²
=(726a²-600a²)/100
=126a²/100
therefore the increase percent=(126a²/100)/6a²×100
=21
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