Math, asked by euroqureshi, 9 months ago

An efficiency study of the morning shift at a certain factory indicates that an average worker who arrives on the job at 7:00 A.M. will have assembled ‘y’ number of Television sets ‘x’ hour later. y=f(x)= -x^3+5x^2+ 12x How many sets will such a worker have assembled by 04:00 PM? How many sets will such a worker assemble between 11:00 AM and 12:00 noon?

Answers

Answered by suyashm7898
1

50 seats ok got it bye bye

Answered by amitnrw
1

Given : An efficiency study of the morning shift at a certain factory indicates that an average worker who arrives on the job at 7:00 A.M. will have assembled ‘y’ number of Television sets ‘x’ hour later.

y=f(x)= -x³+5x²+ 12x  

To find : How many sets will such a worker have assembled by 04:00 PM? How many sets will such a worker assemble between 11:00 AM and 12:00 noon?

Solution:

y=f(x)= -x³+5x²+ 12x

x = number of hours worked from 7:00AM

y = number of Televisions assembled

7:00AM to 04:00 PM  = 9 hrs

=> x = 9

=> y = f(9)  =   -9³+5(9)²+ 12(9)

=>  y = f(9)  =   -729 + 425+ 108

=> y = f(9)  = -196

number of Television sets can not be -ve hence looks mistake in data

assemble between 11:00 AM  ( 4 hrs from 7:00 AM )and 12:00 noon  ( 5 hrs from 7:00 AM )

=   f(5) - f(4)

=   -5³+5(5)²+ 12(5) - ( -4³+5(4)²+ 12(4))

=  -125 + 125 + 60 - ( -64 + 80 + 48)

=  60 -  64

= - 4

looks mistake in equation

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