Question

an effort 4 n is applied to lift a load of 20 and if the effort arm is a 5m calculate the following load arm input work output work​

Answer 1

Step-by-step explanation:

question 18, Laura found that the box is a little big to keep inside the locker. She realised the fact that a cubical box will exactly fit inside the locker. Find the smallest number by which 9000 must be divided so that the dimensions of the box form a perfect cube.

Answer 2

Step-by-step explanation:

 SP of 1 Radio = 2288

SP = CP + Profit

2288 = x + 10x/ 100

2288 = 11x / 100

x = 2288 * 100  / 11

x = 2080 = 18720 / 9

2nd Radio SP = 2288

CP = SP + Loss

x = 2288 + 10x/100

9x / 10 = 2288

x = 2288 * 10 /9

x = 2542.2222222.... = 22880 / 9

Total SP = 2288 + 2288 =4576 = 41184 / 9

Total CP = (22880 + 18720) / 9

= 41600 / 9

AS Cp > SP then it is a loss

Loss = (41600 - 41184 ) / 9

Loss = 416 / 9

Loss % = (416 / 9 )* (9 / 41600) * 100

Loss% = 1%