Question

an effort force of 20 n is used to lift a load of 60 n by a machine.calculate the mechanical advantage of a machine?​

Answer 1

Answer:

Let us take first case,

in which load=20N,effort=5N,VR=20

Efficiency=

VR∗effort

load

∗100

Putting above values, we get

Efficiency=

20∗5

20

∗100=20%

In second case we have. load=30N,efoort=6N,VR=20

Efficiency=

VR∗effort

load

∗100

Putting values we get,

Efficiency=

20∗6

30

∗100=25%

HenceEfficiency=25%,20%

Answer 2

Provided that:

• Effort force = 20 Newton
• Load = 60 Newton

To calculate:

• Mechanical advantage

Solution:

• Mechanical advantage = 3

Using concept:

• Mechanical advantage formula

Using formula:

• ${\small{\underline{\boxed{\pmb{\sf{MA \: = \dfrac{l}{e}}}}}}}$

Where, MA denotes mechanical advantage, l denotes load and e denotes effort.

Required solution:

${\sf{:\implies Mechanical \: advantage \: = \dfrac{Load}{Effort}}}$

${\sf{:\implies MA \: = \dfrac{l}{e}}}$

${\sf{:\implies MA \: = \dfrac{60}{20}}}$

${\sf{:\implies MA \: = \dfrac{6}{2}}}$

${\sf{:\implies MA \: = 3}}$

• Henceforth, mechanical advantage is 3.