Question

An effort of 100 N is applied to lift a load of 500Nn. If the distance between load and fulcrum is 20cm, calculate the effort distance.​

Answer 1

Answer:

An effort of 100 N is applied to lift a load of 500Nn. If the distance between load and fulcrum is 20cm, the effort distance will be $100cm$​

Explanation:

• According to the principle of levers,

        Load $\times$ Load arm  =Effort $\times$ Effort arm

• If L is the load and E is the effort. The distance between the load and fulcrum be the load arm$L_d$ and the distance between effort and fulcrum be the Effort arm$E_d$.

        So,

         $L\times L_d = E\times E_d$    ...(1)

In the question, it is given that,

$L = 500\ N$                   $E = 100\ N$

$L_d = 20\ c m$                 $E_d = ?$

Using equation (1),

$E_d = \frac{L\times L_d}{E}$

Substitute the values into the above equation.

$E_d = \frac{500\times 20}{100} = 100 cm$

Effort distance is $100cm$