An effort of 12 KGF is applied on a machine for the moment it off a load of 120 KGF find the mechanical advantage of the machine ?
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Hey dear the solution goes like this,
Mechanical advantage= output force/input force
as per the question,
input force= 12 KGF
output force=120 KGF
so as per the formula,
M.A.= 120/12=10
so the mechanical advantage of machine will be 10.
Here the mechanical advantage will not have any unit as it is a ratio of same quantities.
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