An effort of 12 kgf is applied on a machine for the movement of a load of 120 kgf. Find the Mechanical Advantage of the Machine.
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ANSWER
the mechanical advantage of machine is 5.7
Explanation:
Given that,
Load = 120 kgf
Effort = 21 kgf
We know that,
Mechanical Advantage = load/ effort
M.A=
E
L
M.A=
21
120
M.A=5.7
Hence, the mechanical advantage of machine is 5.7
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0
Answer:
The amount of heat (H) produced is given by the joule’s law of heating as H= Vlt
Where,
Current, I = 5 A
Time, t = 30 s
Voltage, V = Current x Resistance = 5 x 20 = 100V
H= 100 x 5 x 30 = 1.5 x 104 J.
Therefore, the amount of heat developed in the electric iron is 1.5 x 104 J.
Explanation:
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