Question

An effort of 15 kgf is applied on a machine for the movement of load of 150 kgf . Find the mechanical advantage of the machine.

Answer 1

Answer:

10. I hope this helps...... Please mark it as brainliest....

Explanation:

Effort = 15 kgf

Load = 150 kgf

Mechanical Advantage = $\frac{load}{effort}$

                                        = $\frac{150 kgf }{15 kgf }$

                                        = 10