An effort of 25 kgf is applied on a machine for the movement of a load of 250 kgf. Find the machnical advantage of the machine.
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Explanation:
REF.Image.
Length of lever = Effort arm = AE
Load arm AB = 0.1 m
Effort E = 50 kgf
Load L = 750 kgf
AE×50=750×0.1
AE=
50
750
×
10
1
=1.5m
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