Physics, asked by shweta2199, 5 months ago

An effort of 25 kgf is applied on a machine for the movement of a load of 250 kgf. Find the machnical advantage of the machine.​

Answers

Answered by Anonymous
1

Explanation:

REF.Image.

Length of lever = Effort arm = AE

Load arm AB = 0.1 m

Effort E = 50 kgf

Load L = 750 kgf

AE×50=750×0.1

AE=

50

750

×

10

1

=1.5m

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