Physics, asked by manvimangal1609, 19 days ago

An effort of 50 N is applied on a simple machine through a distance of 0.6m.As a result of load 300N moves through a distance 7.5cm, Calculate Work done by a machine (joule)

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Answered by ruhisinghlife40
0

Answer:

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In a lifting machine, an effort of 500 N is to be moved by a distance of 20 m to raise a load of 10000 N by a distance of 0.8 m. Determine the velocity ratio and mechanical advantage?

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Solution

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Correct option is

D

25 and 20

Distance moved by effort is 20m,that of load is 0.8m

VR=

L

d

E

d

VR=

0.8

20

VR=25

the load is 10,000N and effort=500N

MA=

effort

d

load

d

MA=

500

10000

MA=20

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