Question

an effort of 5kgf is applied on a machine for movement of load of 100kgf. calculate mechanical advantage​

Answer 1

Explanation:

Given that,

Load = 120 kgf

Effort = 21 kgf

We know that,

Mechanical Advantage = load/ effort

M.A=

E

L

M.A=

21

120

M.A=5.7

Hence, the mechanical advantage of machine is 5.7

Answer 2

To Find :

The mechanical advantage of the machine

Given :

• Load = 100 kgf
• effort = 5 kgf

We know that :

• Mechanical Advantage = load/effort

Solution :

Given, load = 100 kgf

effort = 5 kgf

M.A = load/effort

or, M.A = 100/5

or, M.A = 20

hence, the M.A of the machine is 20