an egg falls off atable the floor is 0.8m from the table top g10/s^2 how long will take the egg to reach the floor?
Answers
Answer:
the egg will take 0.4 seconds to reach the floor
Explanation :
using the equation x=ut + 1/2 gt^2
here u = 0 m/s
g is given to be 10 m/s^2
so , t^2 = 2x/g = 16/100
therefore, t= 0.4 seconds
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Given : An egg falls off a table. The floor is 0.8 m from the table top.
To Find :
a) Calculate the time taken to reach the ground.
b) Calculate the velocity of impact with the ground.
Solution:
egg falls
=> initial velocity u = 0
a = g = 10 m/s²
floor is 0.8 m from the table top
=> s = height = 10 m
Using formula
S = ut + (1/2)at²
=> 0.8 = 0 + (1/2)(10) t²
=> t² = 0.16
=> t = 0.4 sec
time taken to reach the ground is 0.4 secs
V = u + at
=> V = 0 + 10 * 0.4
=> V = 4 m/s
velocity of impact with the ground. is 4 m/s
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