Physics, asked by akshit56, 1 year ago

an elastic spring of force constant K is compressed by an amount x .Show that its PE is 1/2kx^2

Answers

Answered by mathemagician
4
change in potential energy is equal to work done by conservative force.. so F= KX. NOW INTEGRATE BOTH SIDES AND YOU WILL GET W= 1/2KX^2
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