Question

an elastic wire is stretched from elongation x=0 to x=5mm the work done is 10J then work done to stretch X= 5mm to x=10mm​

Answer 1

Answer:

30 J

Explanation:

5mm=0.005 m, 10mm= 0.010 m

w=¹/₂ K(X₁ ² - X₂ ²)

10=¹/₂K(0.005² -  0²)

K=20÷0.000025=800000

W=¹/₂K(0.01²-0.005²)=0.5×800000×0.000075=30