An elavatory stationary at ground level descends into a mine shaft at the rate of 5 m per minute.What will be its position be after 1 hour? What will be its position be from the ground , after 45 minutes,if it begins to descend from 15 m above the ground?
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Answer:
after 1hour=5×60=300. It's position will be=15-300=-285=285m below the ground.
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Answer:- 285m below the ground.
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