An elecron Jumps from an atom in such a way that its kinematic energy change from X to x/9 . The change in it's potential energy is
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Answer:
The change in kinetic energy [KE]:-
The change in kinetic energy [KE]:-x - x/4 = + 3x/4
The change in kinetic energy [KE]:-x - x/4 = + 3x/4Now we know that KE = mod of TE
The change in kinetic energy [KE]:-x - x/4 = + 3x/4Now we know that KE = mod of TETherefore TE = 3x/4
The change in kinetic energy [KE]:-x - x/4 = + 3x/4Now we know that KE = mod of TETherefore TE = 3x/4Now there is another formula that is:-
The change in kinetic energy [KE]:-x - x/4 = + 3x/4Now we know that KE = mod of TETherefore TE = 3x/4Now there is another formula that is:-PE [Potential energy] = 2 TE
The change in kinetic energy [KE]:-x - x/4 = + 3x/4Now we know that KE = mod of TETherefore TE = 3x/4Now there is another formula that is:-PE [Potential energy] = 2 TEPE = 2 * 3x/4
The change in kinetic energy [KE]:-x - x/4 = + 3x/4Now we know that KE = mod of TETherefore TE = 3x/4Now there is another formula that is:-PE [Potential energy] = 2 TEPE = 2 * 3x/4PE = + 3x/2.