An electie lamp of 100 m, a toaster of resistance so , and a water filter of resistance 500 are connected
in parallel to a 220 V source. What is the resistance of an electric iron connected to the same source that
takes as much current as all three appliances, and what is the current through it?
Answers
Answer:
I in electric lamp =100220
I in toaster =50220
I in filter =500220
⇒ Total current =100220+50220+500220
=50220(21+1+101)
=522×58
=25176
=7A
⇒R if iron =IV=25176220
=31.25Ω
Hence, the answer is 31.25Ω.
Answer:
7.04A
Explanation:
(1) Total resistance (R) can be calculated as shown below.
1/R = 1/R₁ + 1/R₂ + 1/R₃
1/R = 1/100 + 1/50 + 1/500
1/R = ( 5 + 10 + 1 )/500
1/R = 16/500
500/16 = R
Total Resistance (R) = 500/16 Ω
R = 31.25 Ω
(2) According to ohm’s law the current through a conductor between two points is directly proportional to the voltage across the two points.
V ∝ I or V = IR
R is constant called resistance.
R = V/I
500/16 = 220/I
I = 220 × (16/500)
I = 7.04 A
Therefore, the resistance of the electric iron is 31.25 Ω and the current flowing through it is 7.04 A.