Question

An election having momentum 2.4 x 10^-23 kgms^-1 enters a region of uniform. magnetic field of 0.30 T. The field vector makes with initial velocity A an angle зо of the election. Find the radius of the helical path of the election in the field .

explain step by step.




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Answer 1

Answer:

0.5 mm

The radius of the helical path of the electron in the uniform magnetic field is

r=

eB

mv

⊥

=

eB

mvsinθ

=

(1.6×10

−19

C)×(0.15T)

(2.4×10

−23

kgms

−1

)×sin30

o

=5×10

−4

m=0.5×10

−3

m=0.5mm

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Answer 2

$\huge\mathrm{\pink{Answer}}$

Correct answer is 0.5 mm .

Tip: Please improve your writing.