An election is conducted between two candidates in a city. 50000 enrolled voters did not cast their votes and only 80% of cast voters were valid. If the winning candidate won by 1 0080 votes, the losing candidate got 1 8% of the total valid votes and 26% of the enrolled voters vote nota, then find the total number of enrolled voters?
Answers
Answer: The total enrolled votes are 90,516
Step-by-step explanation:
Let the total cast votes = x
Since, the voters who did not cast their votes = 50000
Thus, the total enrolled votes = (x+50000)
Now, 80 % of total cast votes are valid.
⇒ Valid votes = 80% of x = 0.8 x
The losing candidate got 18% of the total valid votes and 26% of the enrolled voters vote NOTA.
Hence, the losing candidate got votes = 18 % of 8x
= 0.144 x
And, the winning candidate got votes = 0.8x -( 0.144x + 26% 0f (x+5000))
= 0.8x - 0.144x - 0.26x - 130
= 0.396x - 130
According to the question,
(0.396x - 130) - 0.144x = 10080
⇒ 0.252x - 130 = 10080 ⇒ 0.252 x = 10210 ⇒ x = 40,515.873
Hence, the total enrolled votes = 40,515.873 + 50000 = 90,515.873 ≈ 90,516
Answer:
Step-by-step explanation:
there is no 5000 its 50000 so ans should be 150000