Question

An election was contested by two candidates A and B. In all there were 25000 voters.
80% of the votes were polled. If A got 60% of the total votes polled, how many votes did
B get?
Mr Mehta had 3 60000. Out of this money, he gave 20% to his daughter, 35% to his son,
much did he donate?​

Answer 1

Step-by-step explanation:

Member of voters = 80,000

Total vote polled = 80% of 80,000 = \frac { 80 }{ 100 } x 80,000 = 64,000

Vote polled to A = 60% of 64,000 = \frac { 60 }{ 100 } x 64000 = 38,400

Vote polled to B = Total vote polled – vote polled to A = 64,000 – 38,400 = 25,600