Question

An election was contested by two candidates A and B .in all there were 25000 voters. 80% of votes were polled.if A got 60% of the total vptes polled how many votes did B get?

Answer 1

100%=2500
20%= 5000
so the and 5000

Answer 2

Answer:

$Number \: votes \: B\: get = 8000$

Step-by-step explanation:

$Total \: voters \: in \: constituency = 25000$

$A \: and \: B \: are \: two \: contestants.$

$Number \: of \:votes \: Polled \\ = 80\% \: of \: Total \:votes$

$= 80\% \times 25000$

$= \frac{80}{100} \times 25000$

$= 20000$

$Number \: of\:votes \: A \: get \\= 60\% \:of \: Number \: of \: votes \: polled$

$= 60\% \times 20000$

$= \frac{60}{100}\times 20000\\= 12000$

$Now,\\Number \: votes \: B \: get \\= Number \: of \: votes \: polled - Number \: votes \: A \: get$

$= 20000 - 12000\\=8000$

Therefore.,

$Number \: votes \: B\: get = 8000$

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