Physics, asked by srisayan7619, 1 year ago

An election with charge e enters a uniform magnetic field B with a velocity V. The velocity is perpendiculer to the magnitic field. The force on the charge e is given by (F)= Bev obtain the dimensions of B.

Answers

Answered by singhrajveer7779
3

The dimensions of Flux Density, B is M/T2I.

Explanation:

If charge moving at right angles to the field

F = -Bev for an electron ( e = charge on an electron)

Remember that the direction of conventional current is opposite to that of the electron.

Here, F is force measured in newtons (N)

B is flux density (the strength of a magnetic field I.e No. of magnetic lines of force from magnet per unit area) measured in teslas (T, named after Nikola Tesla)

So, The dimensions of Flux Density, B is MT^-2I^-1.

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