Question

An electric an electric dipole is formed by + 4 microcoulomb and -4 microcoulomb charges at 5 mm distance calculate the dipole moment and give its direction

Answer 1

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Answer 2

Given:

The magnitude of first charged particle = +4μC (micro Coulomb)

The magnitude of second charged particle = -4μC (micro Coulomb)

Distance between two charged particles = 5 mm (millimeter)

To find:

Dipole moment=?

Direction=?

Solution:

• The dipole moment of the charged particle can be calculated from the product of its magnitude of charge and the distance between them.
• Dipole moment has Standard International unit as Coulomb meter.
• Therefore we need to first convert the units into meters.

    => 4 μC = 4 × 10⁻⁶Cm

    => 5 mm = 5 × 10⁻³m

    Dipole moment (μ) = magnitude of charge (q) × distance b/w charges (d)

    => Dipole moment (μ) = 4 × 10⁻⁶Cm × 5 × 10⁻³m

    => Dipole moment (μ) = 20 × 10⁻⁹ Cm

    => Dipole moment (μ) = 2 × 10⁻⁸ Coloumb.meter

Hence, the two charges have a dipole moment 2 × 10⁻⁸ Coulomb meter and are directed towards the positive side.