An electric appliance of power 3Kw is used for 2hours a day,for 30 days.If the total cost of electricity is ₹810,what will be the rate of electricity per unit?
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Answer:
Given,
Power (P) = 3 kW
= 3000 W
Time (t) = 2 hrs
Total Units Consumed in a day = Pt/1000
= (3000*2)/1000
= 6 kWh
Total Units Consumed in a month = (6*30) kWh
= 180 kWh
If the cost of 180 kWh is Rs. 810,
Cost of 1 kWh is = Rs. (810/180)
= Rs. 4.5
The Cost of 1 kWh is Rs. 4.5
I hope this helps.
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