Question

An electric appliance of power 3Kw is used for 2hours a day,for 30 days.If the total cost of electricity is ₹810,what will be the rate of electricity per unit?
please answer fast !!

Answer 1

Answer:

Given,

Power (P) = 3 kW

= 3000 W

Time (t) = 2 hrs

Total Units Consumed in a day = Pt/1000

= (3000*2)/1000

= 6 kWh

Total Units Consumed in a month = (6*30) kWh

= 180 kWh

If the cost of 180 kWh is Rs. 810,

Cost of 1 kWh is = Rs. (810/180)

= Rs. 4.5

The Cost of 1 kWh is Rs. 4.5

I hope this helps.