Question

An electric appliance of power 4.5kWh is used for 1hour 20minutes. find the electrical energy consumed in
1.kWh
2.joules

Please answer​

Answer 1

Answer :-

Given :-

• Power = 4.5 kW
• Time = 1 hour 20 min = 1 ⅓ hour

To Find :-

Electrical energy consumed in

• kWh
• Joule

Solutuon :-

We know that,

Energy = Power × Time

Substituting the values :-

Energy = 4.5 × 1 ⅓

= 4.5 × 4 / 3

= 6

Electrical energy = 6 kWh

Now, converting into joule :-

1 kWh = 3.6 × 10⁶ J

6 kWh = 6 × 3.6 × 10⁶ J

= 21.6 × 10⁶

= 2.16 × 10⁷

Electrical energy = 2.16 × 10⁷ J

Answer 2

Given :-

$~~~~$

• Power = 4.5 kW
• Time = 1 hour 20 min = 1 ⅓ hour

$~~~~$

To find :-

$~~~~$

Electronic energy consumed in

• kWh
• Joule

$~~~~~$

Solution :-

$~~~~$

★ As we know that,

$~~~~$

• Energy = Power × Time

$~~~~$

Substituting the values :

$~~~$

Energy = 4.5 × 1 ⅓

$~~~~~~~~~~~~$ = 4.5 × 4/3

$~~~~~~~~~~~~$ = 6

$~~~~$

Electrical energy = 6 kWh

$~~~~$

Now converting into joul :

$~~~~$

1 kWh = 3.6 × 10 J

$~~~$

6 kWh = 6 × 3.6 × 10 J

$~~~~~~~~~~~$ = 21.6 × 10

$~~~~~~~~~~~$ = 2.16 × 10

$~~~$

• Electrical energy= 2.16 × 10 J