Physics, asked by sankarinava30, 7 months ago

AN ELECTRIC APPLIANCE WITH A CURRENT OF I AND A RESISTANCE OF R CONVERTS ENERGY TO OTHER FORMS AT A RATE OF P WHEN CONNECTED TO A 120V OUTLET. WHAT WOULD BE THE NEW POWER RATING (IN TERMS OF P ) IS THE RESISTANCE IS DOUBLED ( SAME 120V OUTLET IS USED PLZZZZZZZZZZZZZZZ GIVE ME THE CRT ANSWER PLLZZZZZZZZZ MATES

Answers

Answered by abhinavkoolath

This question tests your understanding of the mathematical relationship between power, current, voltage and resistance. There are three equations of importance:

P = I • ΔV

P = ΔV2 / R

P = I2 • R

One must be careful in using the last equation since an alteration in current will also alter the resistance whenever the voltage is held constant. Thus, the first two equations are of greater importance since they represent equations with one independent variable and the other variable held constant.

Questions.

a. ... the usage rate was doubled to 2t?

b. ... the usage rate was halved?

c. ... an appliance which drew twice the current (at 120 Volts) were used?

d. ... an appliance with twice the resistance (at 120 Volts) were used?

e. ... an appliance with one-half the resistance (at 120 Volts) were used?

f. ... the usage rate was doubled and an appliance with twice the resistance (at 120 Volts) were used?

g. ... the usage rate was halved and an appliance with twice the current (at 120 Volts) were used?

h. ... the usage rate was quartered and an appliance with twice the current (at 120 Volts) were used?

ANSWERS.

a. The new cost would be 2•D.

b. The new cost would be (1/2)•D.

c. The new cost would be 2•D.

d. The new cost would be (1/2)•D.

e. The new cost would be 2•D.

f. The new cost would still be D.

g. The new cost would still be D.

h. The new cost would be (1/2)•D.

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Answered by leadergamerdl2005

Answer:

power p becomes half of its original value

Explanation:

P=VI

P=V(V/R) [By Ohm's law ]

P=(V^2)/R ___________ 1)

if resistance is doubled,

P`=(V^2)/2R

P`=(1/2)(V^2)/R

P`=1/2P

that means power changes to half when resistance is doubled

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