Question

An electric blub of resistance 500 ohm draws a current of 0.4 A from the source. Calculate the power of the blub and the potential difference at its end

Answer 1

The Potential Difference can be calculated by
V=IR
V= 0.4*500= 200Volts

The power of the bulb= V*I= 200*0.4= 80 Watts

Answer 2

so here is your answer

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pls mark brainliest