Question

An electric bulb consumes 160, 000 joules of electric energy. If the resistance of its filament is 40 Ω and it operates for 1 hour 6 minutes and 40 seconds, find the current flowing through bulb.​

Answer 1

Answer:

Explanation:

Given:

• W = 160,000 joules

• R = 40 Ω

• t = 1 hr 6 min 40 sec = 4,000 s.

where W is energy consumed

R is resistance

And t is time.

To find:

Current flowing through bulb.

Solution:

We know that,

W = I$^{2}$ × R × t

⇒ 160,000 = I$^{2}$ × 40 × 4000

$⇒I^{2} = \frac{160000}{40 \times 4000} = 1$

⇒ I$^{2}$ = 1

$⇒I = \sqrt{1}$

⇒ I = 1A

Thus, current flowing through bulb is 1A.