Question

An electric bulb draws 0.4 A when the voltage is 220 V. Calculate resistance of Filament and the power of the bulb. Calculate the amount of charge that will flow in one hour.​

Answer 1

Given :-

• The current drawn by the electric bulb, I = 0.2 A

• The voltage, v = 220 v

• The amout of electric charge for one hour, Q = ? (Coulomb)

Solution :-

$: \implies \bf Time \: (t )= 1h$

$\longmapsto \sf 60\times 60 \: sec \\ \\\longmapsto \sf = 3600 \: s$

We know that

$\large \red \bigstar \: \: \boxed{ \green{\bf \: \: \: I=\frac { Q }{ t }} \: \: \: }$

Substitute values in formula :-

$\longmapsto \sf0.4=\frac { Q }{ 3600} \\ \\\longmapsto \sf Q= 0.4\times 3600 \\ \\\longmapsto \boxed{ \purple{\sf Q =1440 \: C}}$

∴ Amount of electric charge for one hour is 720 Coulomb

Answer 2

Answer:

1440 Coulomb

Explanation:

V=IR

R=V/I

R=220/0.4

R=550

Q=I×t

Q=0.4 A × 3600 s

Q= 4/10 × 3600

Q=4×360

Q=1440 Coulomb

Hope it helps you