an electric bulb draws 1.2 A current at 6.0 V. Find the resistance bulb
Answers
Answered by
2
Answer:
As,
V= IR
where
v is voltage
I is current and R is resistance.
So
6 = 1.2 × R
R = 5 ohm.
Answered by
6
Answer:
- Resistance of Bulb, R = 5 Ω
Explanation:
Given
- Current drawn by the bulb, I = 1.2 A
- Potential difference, V = 6.0 V
To find
- Resistance of bulb, R =?
Formula required
- Expression for ohm's Law
V = I R
[ Where V is potential difference, I is current and R is resistance ]
- According to Ohm's law the potential difference is directly proportional to the Current and resistance of Conductor.
Calculation
Using expression for Ohm's law
→ V = I R
→ ( 6.0 ) = ( 1.2 ) · ( R )
→ R = ( 6.0 ) / ( 1.2 )
→ R = 60 / 12
→ R = 5 Ω
Therefore,
- Resistance of bulb will be 5 Ω.
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