Physics, asked by aliciasyiem77, 7 months ago

an electric bulb draws 1.2 A current at 6.0 V. Find the resistance bulb​

Answers

Answered by Ryash143
2

Answer:

As,

V= IR

where

v is voltage

I is current and R is resistance.

So

6 = 1.2 × R

R = 5 ohm.

Answered by Cosmique
6

Answer:

  • Resistance of Bulb, R = 5 Ω

Explanation:

Given

  • Current drawn by the bulb, I = 1.2 A
  • Potential difference, V = 6.0 V

To find

  • Resistance of bulb, R =?

Formula required

  • Expression for ohm's Law

        V = I R

[ Where V is potential difference, I is current and R is resistance ]

  • According to Ohm's law the potential difference is directly proportional to the Current and resistance of Conductor.

Calculation

Using expression for Ohm's law

→ V = I R

→ ( 6.0 ) = ( 1.2 ) · ( R )

→ R = ( 6.0 ) / ( 1.2 )

→ R = 60 / 12

R = 5 Ω

Therefore,

  • Resistance of bulb will be 5 Ω.
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