Question

an electric bulb draws 1.5 A current at 9v . find the resistance of the filament of bulb?​

Answer 1

$\textit{\large{\underline{\underline{EXPLANATION:}}}}$

$\sf{Given}\begin{cases}\sf{I=1.5A}\\ \sf{V=9v}\\ \sf{R=?}\end{cases}$

$\textbf{\underline{Using Ohm's Law,,}}</p><p>$

$\mathtt{\boxed{\blue{R=\frac{V}{I}}}}$

$\sf{\implies{R=\frac{9}{1.5}}}$

$\sf{\implies{R=\frac{90}{15}}}$

$\sf{\implies{R=6Ω}}$

Therefore,,

$\sf{\boxed{\blue{R=6Ω}}}$

Hope it helps ❣️❣️❣️

Answer 2

Concept

Ohm's regulation states that the modern-day via a conductor among  factors is at once proportional to the capability distinction throughout the 2 factors. Introducing the regular of proportionality, the resistance, one arrives at the standard mathematical equation that describes this relationship $I=\frac{V}{R}$

Given

The current drawn from the electric bulb is $1.5A$ at the voltage $9V$.

Find

We are asked to find the resistance of the filament of the bulb.

Solution

By considering the given data,

Here, $I=1.5A$ and $V=9V$.

Substitute the values in the relationship $I=\frac{V}{R}$.

$R=\frac{9}{1.5}$

$R=6$ Ω

Hence the resistance of the filament is $6$Ω.

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