Physics, asked by sodhikush1, 9 months ago

An electric bulb draws a current of 0.8 A and works on 250 V on the average 8 hours a day.
a. Find the power consumed by the bulb
b. If the electric distribution company changes Rs 5 for 1 KWH, what is the monthly bill for 60 days

please answer

Answers

Answered by kritikasharma12212
1

Explanation:

⇒ Given

Current(I) : 0.8 A or Ampere.

Volt (V) : 250 V

Time (T) : 8 hours.

⇒ SI Units (To be Taken Care of!)

Current = A or Ampere

Volt = V or Volts

Time = hours.

Power = W or Watts

⇒ Formula to be Used :

⇒Putting values,  

Power =

Power =

Power =

Power =

Power =

∴ Power consumed by bulb in 1 hour = 200Wh

∴Power consumed by bulb in 8 hour = 1600Wh

or Power consumed by bulb in 8 hour = 1.6 kWh

Now,

Power used by bulb in one day = 1.6kWh

Power used by bulb in 60 days = 1.6kWh * 60

Power used by bulb in 60 days = 96kWh

According to Question,

6kWh = ₹ 5

1kWh = ₹

∴ 96kWh = ₹

∴ 96kWh = ₹

∴ 96kWh = ₹ 80

Therefore, Monthly Bill = ₹80.

HOPE IT WILL HELP YOU

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