An electric bulb draws a current of 1 A and works on 250 V on the average 6 hours a day.
a. Find the power consumed by the bulb
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Answer:
Dear Student
Using,
P=V x I
P = 250 x 0.8 = 200W = 0.2kW
Power consumed in a day=0.2 x 8 = 1.6kWh
For one month,
P = 1.6 x 30 = 48kWh
Charge for 1 kWh = 5/6 = Rs. 0.83
Monthly bill = 48 x 0.83=Rs 39.99 = Rs. 40
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Explanation:
Butanol is a four-carbon alcohol with a formula of C₄H₉OH, which occurs in five isomeric structures, from a straight-chain primary alcohol to a branched-chain tertiary alcohol; all are a butyl or isobutyl group linked to a hydroxyl group.
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