An electric bulb having resistance 200ohm draws a current of 2A. Find the power of the bulb whose potential difference at its ends and the energy(in kWh) consumed burning it for 4 hours a day?
with the formula please
Answers
Answered by
1
Explanation:
Power of the bulb,
P = l2R = (1)2 x 200
⇒ P = 200 W
Energy consumed by bulb in 5h in burning
= Power x Time
= 200 x 5
= 1000 Wh = 1 kWh
Answered by
3
Answer:
Power of the bulb,
P = l2R = (1)2 x 200
⇒ P = 200 W
Energy consumed by bulb in 5h in burning
= Power x Time
= 200 x 5
= 1000 Wh = 1 kWh
Explanation:
hope it's helpful
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