An electric bulb having resistance 200ohm draws a current of 2A. Find the power of the bulb whose potential difference at its ends and the energy(in kWh) consumed burning it for 4 hours a day?
with the formula please
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Hello Mate! Here is the answer to your question.
Given:
- Resistance = 200 ohm
- Current = 2 ampere
- Time taken = 4 hours/day
To find:
According to the question, we need to find the value of power in 4 hours a day.
Solution:
By using Ohm's law, we get:
V = I*R
R = V/I
200 = V/2
V = 400 volts
We also know that,
P = VI
P = 400*2
P = 800 watt
Therefore, power consumed for 4 hours would be:
Power = 800*4
Power = 3200 watt (or) 3.2 kw
Hope it helps you!
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