Math, asked by sweetychakma, 2 months ago

An electric bulb having resistance 200ohm draws a current of 2A. Find the power of the bulb whose potential difference at its ends and the energy(in kWh) consumed burning it for 4 hours a day?
with the formula please​

Answers

Answered by ItzFadedGuy
20

Hello Mate! Here is the answer to your question.

Given:

  • Resistance = 200 ohm
  • Current = 2 ampere
  • Time taken = 4 hours/day

To find:

According to the question, we need to find the value of power in 4 hours a day.

Solution:

By using Ohm's law, we get:

\implies{\rm} V = I*R

\implies{\rm} R = V/I

\implies{\rm} 200 = V/2

\implies{\rm} V = 400 volts

We also know that,

\implies{\rm} P = VI

\implies{\rm} P = 400*2

\implies{\rm} P = 800 watt

Therefore, power consumed for 4 hours would be:

\implies{\rm} Power = 800*4

\implies{\rm} Power = 3200 watt (or) 3.2 kw

Hope it helps you!

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