Physics, asked by rajputjatin7926, 8 months ago

An electric bulb illuminates a plane surface. The intensity
of illumination on the surface at a point 2 m away from the
bulb is 5 × 10⁻⁴ phot (lumen/cm²). The line joining the bulb
to the point makes an angle of 60º with the normal to the
surface. The luminous intensity of the bulb in candela
(candle power) is
(a) 40 √3 (b) 40
(c) 20 (d) 40 × 10⁻⁴

Answers

Answered by deshrajsingh1982
1

Answer:

answer is =40√3

I hope it's help you

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