An electric bulb is connected to 220 V supply and draws a current of 0.5A. What is the power rating of the fan?
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Answered by
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V=IR
220=0.5 R
R=440 ohm
P=V²/R=220*220/440=110 W or P=I²R=440/4=110W
220=0.5 R
R=440 ohm
P=V²/R=220*220/440=110 W or P=I²R=440/4=110W
Meghal1:
Thank you
Answered by
2
Hi !
P = ?
V = 220 v
I = 0.5 A
V = I R
R = V / I
= 220/ 0.5
= 440 Ω
P = I²R
= (0.5)² × 440
= 110 W
P = ?
V = 220 v
I = 0.5 A
V = I R
R = V / I
= 220/ 0.5
= 440 Ω
P = I²R
= (0.5)² × 440
= 110 W
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