Question

An electric bulb is connected to a 220V generator. The current is 0.5A. What is

the resistance of the filament of bulb? Also find out the power of the bulb.​

Answer 1

Explanation:

For the 1st bulb, it's just simply 220v x 0.5A = 110 watts. For the 2nd bulb, 5v x 0.5A = 2.5 watts. Resistance is 5v / 0.5A = 10 ohms

Answer 2

Answer:-

• Potential Difference=V=220V
• Current=I=0.5A
• Resistance=R=?
• Power=P=?

According to ohms law

$\boxed{\sf \dfrac{V}{I}=R}$

$\\ \rm\longmapsto Resistance=\dfrac{220}{0.5}$

$\\ \rm\longmapsto Resistance=440\Omega$

$\\ \underline{\boxed{\bf{\therefore Resistance=440Ω}}}$

Now

$\boxed{\sf P=VI}$

$\\ \rm\longmapsto Power=220\times 0.5$

$\\ \rm\longmapsto Power=110W$

$\\ \underline{\boxed{\bf{\therefore Power=110W}}}$