Physics, asked by safwanmujeeb9, 7 hours ago

An electric bulb is connected to a 220V generator. The current is 0.5A. What is

the resistance of the filament of bulb? Also find out the power of the bulb.​

Answers

Answered by muskan146258
6

Explanation:

V=220V

V=220VI=0.5amp

V=220VI=0.5ampP=?

V=220VI=0.5ampP=?We know that

V=220VI=0.5ampP=?We know thatP=V×I

V=220VI=0.5ampP=?We know thatP=V×IP=220×0.5

V=220VI=0.5ampP=?We know thatP=V×IP=220×0.5P=110watt.

Answered by gargdhruv180
0

Explanation:

V = 220V

I = 0.5A

By formula,

V = IR

220V = 0.5A x R

R = 220V/0.5A

R = 440

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