Question

An electric bulb is connected to a power supply!on 220v if 0.8A electric current is passing through out it then calculate power of bulb​

Answer 1

Given:-

• Potential difference ,V = 220v

• Current ,I = 0.8 A

To Find:-

• Power ,P

Solution:-

As we know that Power is defined as the rate of consumption of energy at per unit time .

• P = VI

Substitute the value we get

→ P = 220 × 0.8

→ P = 176 W

Therefore , the power of bulb is 176 Watt.

Additional Information!!

Potential Difference: The potential difference between two point in an electric circuit carrying some current as the work done to move a unit charge from one point to the other.

Potential difference = Work done /Charge.

V = W/Q

here

V is the potential difference

W is the work done

Q is the charge

✧ SI unit of electric potential energy is volt (V).

✧ 1 volt : The potential difference between two points in a current carrying conductor when one joule of work is done to move a charge of one coulomb from one point to other.

1 Volt = 1Joule/1Coulomb

Answer 2

Answer:

$\large\red{\boxed{given - }}$

• Potential difference , V = 220v

• Current ,1 = 0.8 A

$\large\red{\boxed{find - }}$

• Power ,P

$\large\red{\boxed{Formula - }}$

$\bf\green{P \:= \:VI}$

$\large\red{\boxed{Solution- }}$

• Substitute the value we get

» P = 220 x 0.8

» P = 176 W