An electric bulb is designed to consume 55w when operated at 110v
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Power = 55W, Voltage = 110V, Resistance = V2/P
= (110 x 110)/55
= 220Ω
frequency (f) = 50Hz,
ω= 2πf
= 2π × 50
= 100π
Current in the circuit
Voltage drop across the resistor
=> (220)2 + (100πL)2 = (440)2
=> 48400 + 104π2L2 = 193600
104π2L2 = 193600 – 48400
=> L = 1.2135
≈ 1.2Hz
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