Physics, asked by lalusony1982, 2 months ago

an electric bulb is labelled 40W 200V calculate the current flowing throughough it
what is the resistance of filament
how much heat developed if it work for 5 minutes ​

Answers

Answered by twinklingstar19
0

Answer:

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Answered by piyushnath005
1

Answer:

here is your ans. mate

Explanation:

P=V^2/R

P:Power dissipation in bulb, V:Voltage across bulb, R:Resistance of bulb.

Now, bulb is rated as 40W, 200V. This simply means that the bulb will dissipate 40W of power when 200V is applied across it. Using this data, we can find the resistance of the bulb. So, R=V^2/P.

So, resistance of bulb is 200^2/40=1000 ohms.

Now, when supply voltage is 100V, then power dissipation is V^2/R=100^2/1000= 10W

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