an electric bulb is marked 100 volt to 200volt . Calculate its resistance and current which flows through it when connected to a 220 volt main .
shivam8899:
it may be An electric bulb is marked 100 Watt to 200volt
plzz tell the answer
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At first, you have to understand why bulb glows. It is because heat produced there due to resistance.
The voltage V is related to power P by the formula
,P = I x RI is the current through the resistance where the voltage is applied.
Again,V=IR.
So, P= V^2 / R Or, R= V^2/P
Here, R = (200)^2 /100= (200 x 200) / 100 = 400 ohms.
Putting this back in the eqn
V=IR
now it connected with 220 Volt so
I = 220/400 = 0.55 Ampere
The voltage V is related to power P by the formula
,P = I x RI is the current through the resistance where the voltage is applied.
Again,V=IR.
So, P= V^2 / R Or, R= V^2/P
Here, R = (200)^2 /100= (200 x 200) / 100 = 400 ohms.
Putting this back in the eqn
V=IR
now it connected with 220 Volt so
I = 220/400 = 0.55 Ampere
is my answer correct
agar mujhe pta hota to me puchti kyu?
hihihi ...btw trust me this is correct
no ur answer is correct or not but plz tell the formula you used in solving
P = V^2/ R ....nd in end when voltage will change,then i use V = IR
i did not study this formula
so now u should
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