An electric bulb is marked as 100 W-220 V. Then its resistance is
a) 282 ohm
b) 968 ohm
c) 484 ohm
The potential difference between the points A and B in the figure is
5.
УА
АЛЛ
M yam
6.
7
a) 3V
b) SV
c) 6V
d) 9V
A circular coil of radius 5 cm and 50 turns carries a current of 3 ampere. The magnetic
dipole moment of the coil is nearly
(a) 1.0 A m
(b) 1.2 A m?
(c) 0.5 A m? (d) 0.8 A m
Three wires of equal lengths are bent in the form of loops. One of the loops is circle,
another is a semi-circle and the third one is a square. They are placed in a uniform
magnetic field and same electric current is passed through them. Which of the
following loop configuration will experience greater torque?
(a) Circle
(b) Semi-circle
(c) Square
(d) All of the above
Answers
Answer:
ur answer for the first question is ...
Explanation:
100 Watts tells us the product of current and voltage, being the Joule’s law power equation.
220 Volts expresses the voltage multiplier.
Therefore, with the product being 100 W and one of the multipliers being 220 V, the value for current can be calculated under Joules law:
wattage = current • voltage
current = voltage ÷ wattage
current = 100 W ÷ 220 V
current = 0.4545 amperes
With current determined, Ohm’s law can be used to calculate resistance.
resistance = voltage ÷ current
resistance = 220 volts ÷ 0.4545 amperes
resistance = 484.0484 ohms
Logically, if two of three quantities of a specific ratio are known, then the third quantity can be calculated.
A permutation of Joule's law, its simple ratio I = E ÷ P does not show us all three quantities for the Ohm’s law ratio I = E ÷ R but does utilise two of the three.
Likewise, Ohm's law does not show all three quantities for the simple permutation of the Joule's law ratio, I = E ÷ P.
Specifications for the bulb tell its full story with a little help from relevant equations that form bases for electronic circuit function and load