An electric bulb is marked as240v, 60w. the resistance of its filament is
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We know that P = V^2 / R
so, 60 = (240)^2 / R
Now, R = 57600 / 60
R = 960 ohm
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so, 60 = (240)^2 / R
Now, R = 57600 / 60
R = 960 ohm
I hope it help u
please mark as brainleist and follow me
harishmanhas:
correct answer
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Answer:
The resistance of its filament is 960ohm
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