Physics, asked by harishmanhas, 1 year ago

An electric bulb is marked as240v, 60w. the resistance of its filament is

Answers

Answered by NileshDangi
40
We know that P = V^2 / R
so, 60 = (240)^2 / R
Now, R = 57600 / 60
R = 960 ohm
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harishmanhas: correct answer
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Answered by chandramohanmishra02
0

Answer:

The resistance of its filament is 960ohm

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