Question

An electric bulb is rated 200v and100 watt when it is operated on 110 v power consumed will be

Answer 1

Explanation:

P = V^2/R  

If V = 220 V we have

100 W = 220^2/R

R = 220^2/100 Ω = 484 Ω. This is the resistance of the bulb.

When V = 110 V, power consumed =  V^2/R = 110^2/484 = 25 W.

So, 25 W power is consumed when it is operated on 110 V.

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Answer 2

Answer:

power of bulb operating at 110 v will be 200 Watt

Explanation:

V1 = 220 v   , P1 = 100 W     ,V2 = 110 v   , P2 = ?

P1 V1 =  P2 V2  

P2 = P1 V1 / V2

P2 = 220 x 100 / 110

P2 = 200 Watt