Question

An electric bulb is rated 220 5 volt and 100 watt when it is operated on 110 volt the power sharing will be

Answer 1

Given, P₁= 100 W

V₁= 220V

We know, P= V²/R,

So R= V²/P₁= 220²/100 = 484Ω

If, V= 110V,

P= V²/R= 110²/484= 25W

Answer 2

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