An electric bulb is rated 220 V and 100 W. When it is operated on 110 V, thepower consumed will be –(a) 100 W (b) 75 W (c) 50 W (d) 25 W
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Just guessing since power is halved so mist the potential difference so option c
muskan186:
yes power =50 W
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Resistance of electric bulb = V²/P = 220*220/100 = 484 ohm
When operated on 110 V power consumed = V²/R = 110*110/484 = 25 W
So answer is option d = 25 W
When operated on 110 V power consumed = V²/R = 110*110/484 = 25 W
So answer is option d = 25 W
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